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Bis(1H-imidazole-κN3)bis­(4-methyl­benzoato-κO)zinc(II) 4-methyl­benzoic acid disolvate

✍ Scribed by Gu, Chang-Sheng ;Hao, Xiao-Min ;Song, Wen-Dong ;Yan, Jian-Bin

Publisher
International Union of Crystallography
Year
2007
Tongue
English
Weight
275 KB
Volume
63
Category
Article
ISSN
1600-5368

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✦ Synopsis

The molecular structure of the title compound, [Zn(C~8~H~7~O~2~)~2~(C~7~H~6~N~2~)~2~]·2C~8~H~8~O~2~, is composed of a mononuclear Zn^II^ complex, which possesses twofold rotation symmetry, and two uncoordinated 4-methylbenzoic acid molecules. The Zn^II^ atom displays a four-coordinate distorted tetrahedral configuration, formed by two carboxylate O atoms of two monodentate 4-methylbenzoate ligands and two N atoms of two benzimidazole molecules. In the crystal structure, complex molecules are linked by the 4-methylbenzoic acid molecules via N—H...O and O—H...O hydrogen bonds, giving rise to the formation of a supramolecular structure.

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The title compound, [Ni(C 8 H 5 O 3 ) 2 (C 3 H 4 N 2 ) 2 (H 2 O) 2 ], is isostructural with the manganese analogue. The Ni atom, which lies on a centre of inversion, is coordinated by two imidazole and two water ligands, as well as by the formylbenzoate groups, in an all-trans octahedral geometry.

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The title dinuclear Co II complex, [Co 2 (C 8 H 7 O 2 ) 4 (C 12 H 8 N 2 ) 2 -(H 2 O)], has C 2 symmetry with the coordinated water O atom located on a twofold axis. Two Co II ions are bridged by two methylbenzoate (MBZ) anions and one water molecule. Each Co II ion displays a distorted octahedral co