The absorption spectrum of CzHsF has been measured in the region down to 1150 A with absorption maxima at 1290, 1240 and 1180 A and has been interpreted with Rydberg transitions from the o(K) and pseudo 5r(CH3) orbitals to the carbon 3s and 3p orbitals.
Solvent effects on the ultraviolet absorption spectrum of mercury atom
โ Scribed by M.V. Buturlimova; G.Ya. Zelikina; M.B. Kiseleva
- Publisher
- Elsevier Science
- Year
- 2008
- Tongue
- English
- Weight
- 186 KB
- Volume
- 880
- Category
- Article
- ISSN
- 0022-2860
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โฆ Synopsis
Absorption spectrum of mercury dissolved in hexane and heptane in the region 280-180 nm was found to consist of three bands. These bands were assigned to the 1 S 0 ? 3 P 1 transition (A band, k = 254 nm), to the 1 S 0 ? 3 P 2 transition (B band, k = 226 nm) and the 1 S 0 ? 1 P 1 transition (C band, k = 190 nm) of a mercury atom placed into a liquid cell. The B and C absorption bands of mercury in liquid solutions were observed for the first time. It was found that the A band and the C band have, respectively, distinct doublet and triplet structure, while the doublet structure of the B band is only slightly seen. The oscillator strengths of all three bands of mercury in solutions were estimated. The structure of the C, A and B bands of mercury in solutions most probably results from the removal of the degeneracy of the excited states 1 P 1 , 3 P 1 and 3 P 2 of a mercury atom, placed into a cell of low symmetry.
๐ SIMILAR VOLUMES
The variation with pressure of the two components of the electronic origin band of the first singlet-singlet transition in crystalline naphthalene is considered. A model is constructed which gives a satisfactory account of this variation. The splitting contains both Coulomb and overlap-dependent ter
The nature of the solvent has a small influence on the position of the longest wavelength absorption band and the oscillator strength (So-~ S l transition) of (BDH) + Cl-. A linear correlation between the molar excitation energy of (BDH) + Cl-and the refractive index function f(n) = (n 2\_ 1 )/(2n 2