(2E)-3-(4-Chlorophenyl)-1-(3-hydroxyphenyl)prop-2-en-1-one
✍ Scribed by Butcher, Ray J. ;Jasinski, Jerry P. ;Yathirajan, H. S. ;Lakshmana, K. ;Narayana, B.
- Publisher
- International Union of Crystallography
- Year
- 2007
- Tongue
- English
- Weight
- 947 KB
- Volume
- 63
- Category
- Article
- ISSN
- 1600-5368
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✦ Synopsis
Two new chalcones of general type (2E)-1-(3-hydroxyphenyl)-3-(4-R-phenyl)prop-2-en-1-one are reported, one where R = chloro, C 15 H 11 ClO 2 , in the present paper, and one where R = methyl, C 16 H 14 O 2 , in the preceding paper [Butcher, Jasinski, Narayana, Lakshmana & Yathirajan (2007). Acta Cryst. E63, o3660]. In both structures, the 3-hydroxyphenyl and 4-(methyl/chloro)phenyl groups are coplanar with each other and also with the propyl-2-ketone oxygen. Crystal packing is stabilized by intermolecular O-HÁ Á ÁO hydrogen bonding between the hydroxyl hydrogen and the propyl-2-ketone oxygen.
📜 SIMILAR VOLUMES
The title compound, C 15 H 11 ClO 2 , is almost planar and adopts an E configuration. The dihedral angle between the two benzene rings is 10.76 ( 6) . An intramolecular O-HÁ Á ÁO hydrogen bond generates an S(6) ring motif. Molecules are arranged in layers approximately parallel to the (204) plane an
Two new chalcones of general type (2E)-1-(3-hydroxyphenyl)-3-(4-R-phenyl)prop-2-en-1-one are reported, one where R = methyl, C 16 H 14 O 2 , in the present paper, and one where R = chloro, C 15 H 11 ClO 2 , in the following paper [Butcher, Jasinski, Narayana, Lakshmana & Yathirajan (2007). Acta Crys
Geometric parameters of the title compound, C~16~H~14~O~3~, a chalcone derivative, are in the usual ranges. The C=C double bond is __trans__ configured. The molecule is essentially planar (r.m.s. deviation for all non-H atoms = 0.066 Å). The molecular conformation is stabilized by an O—H...O hydroge