## Abstract The peptide N‐Ac‐dehydro‐Phe‐L‐Val‐L‐Val‐OCH~3~ (C~22~H~31~N~3~O~5~) was synthesized by the usual workup procedure and finally by coupling the N‐Ac‐dehydro‐Phe‐L‐Val‐OH to valine methyl ester. It was crystallized from its solution in acetonitrile‐water mixture at 4°C. The crystals belon
α,β-Dehydro-amino acid residues in the design of peptide structures: Synthesis, crystal structure, and molecular conformation of two homologous peptides—N-Ac-Dehydro-Phe-L-Leu-OCH3 and N-Ac-Dehydro-Phe-NorVal-OCH3
✍ Scribed by Pushkar Sharma; Punit Narula; Tej P. Singh
- Publisher
- Wiley (John Wiley & Sons)
- Year
- 1994
- Tongue
- English
- Weight
- 470 KB
- Volume
- 34
- Category
- Article
- ISSN
- 0006-3525
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✦ Synopsis
The dehydro-residue containing peptides N-Ac-dehydro-Phe-L-Leu-OCH3 ( I ) and N-Acdehydro-Phe-NorVal-OCH, (11) were synthesized by the usual workup procedures. The peptides crystallize from their solutions in methanol in space group P6,: ( I ) a = b = 12.528(2) A, c = 21.653(5) A; (11) a = b = 12.532(2) A, c = 21.695(4) A. Thestructures were determined by direct methods. Both peptides adopt similar conformations with @,# of dehydro-Pheasfollows: ( I ) -57.0(5)" and -37.0(5)"; (11) -56.0(5),' and-37.5(5)".
The observed data on dehydro-Phe when placed at the ( i + 1) position show that the &J,# values of dehydro-Phe are either -60°, 140" or -60", -30". The conformation of -Boo, 140" can be accommodated only with a flexible residue at the ( i + 2 ) position while the 4,$ values of -60", -30" are obtained with a bulky residue at the ( i + 2 ) position as in the present structures. The molecules are packed in a helical way along the c axis. These are held by two strong intermolecular hydrogen bonds involving both NH as donors and acetyl group and dehydro-Phe oxygen atoms as acceptors.
📜 SIMILAR VOLUMES
The peptide N-Boc-L-Gly-dehydro-Phe-NHCH, was synthesized by the combination of N-Boc-L-Gly-dehydro-Phe azlactone and pethylamine. Th? peptide crystalliqes in orthorhoybic space group P2,2121 with a = 5.679( 2) A, b = 16.423(9) A, c = 19.198(10) A, V = 1791(2) A3, 2 = 4, d m = 1.212(5) Mg m-,, dc =