The structure of a rhombohedral R6 insulin hexamer that binds phenol

✍ Scribed by G. D. Smith; G. G. Dodson

• Book ID: 101719103
• Publisher: Wiley (John Wiley & Sons)
• Year: 1992
• Tongue: English
• Weight: 327 KB
• Volume: 32
• Category: Article
• ISSN: 0006-3525
• DOI: 10.1002/bip.360320422

✦ Synopsis

Different hexameric forms of insulin have been crystallized from a variety of conditions. In the presence of 1% phenol, 1.OM sodium chloride, and at a p H of 8.5, a rhombohedral form is produced with two monomers in the asymmetric unit, space group R3, a = 79.92

A and c = 40.39 A. The structure has been solved and refined, using data between 8.0 and 2.5 8, resolution, to a residual of 0.157. Each of the monomers adopts an R conformation, that is residues Bl-B8 are a-helical. As a result of the T to R transition, an elliptical cavity is created between symmetry-related monomers and is occupied by a phenol molecule. A region of density within bonding distance to one of the zinc ions has been interpreted as an additional phenol molecule.