## Abstract This paper deals with a Hausdorff moment problem with complex exponents, that is, given a sequence of complex numbers __(z~n~)n__ and a fixed space __X__ of functions denned on [0, 1], we ask under which conditions on a sequence (__a__~__n__~)~__n__~ the moment problem __a__~__n__~ = ∫
The Stieltjes Moment Problem with Complex Exponents
✍ Scribed by Antonio J. Duran
- Publisher
- John Wiley and Sons
- Year
- 2006
- Tongue
- English
- Weight
- 835 KB
- Volume
- 158
- Category
- Article
- ISSN
- 0025-584X
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✦ Synopsis
Abstract
In this paper, we characterize the complex sequences (z~n~)~n~ which satisfy the following condition: For each complex sequence (a~n~)~n~, there exists a function f such that the functions t^z^~n~f(t) are Lebesgue integrable and a~n~ = ∫ t^z^~n~f(t)(dt) for all n∫. In this case, we give for every sequence (a~n~)~n~ infinitely many C∫ functions f satisfying some growth conditions in x = 0 and x = + ∫, and such that a~n~ = ∫ t^z^~n~f(t)dt.
Finally, we extend this result for Banach space valued functions.
📜 SIMILAR VOLUMES
Let {c,,}~ ~ be a doubly infinite sequence of real numbers. A solution of the strong Hamburger moment problem is a positive measure tr on (-~x~, c~) such that c, = f\_~ u ~ da(u) for n = 0, ± 1, i 2 ..... A solution of the strong Stieltjes moment problem is a positive measure a on [0, c~z) such that
On the space, A of Laurent polynomials we consider a linear functional L which is positive deÿnite on (0; ∞) and is deÿned in terms of a given bisequence, {c k } ∞ k=-∞ . For each ! ¿ 0, we deÿne a sequence {Nn(z; !)} ∞ n=0 of rational functions in terms of two sequences of orthogonal Laurent polyno
## Abstract The article is devoted to the solution of the infinite‐dimensional variant of the complex moment problem, and to the uniqueness of the solution. The main approach is illustrated for the best explanation on the one‐dimensional case. (© 2007 WILEY‐VCH Verlag GmbH & Co. KGaA, Weinheim)