The number of permutations containing exactly one increasing subsequence of length three
β Scribed by John Noonan
- Publisher
- Elsevier Science
- Year
- 1996
- Tongue
- English
- Weight
- 287 KB
- Volume
- 152
- Category
- Article
- ISSN
- 0012-365X
No coin nor oath required. For personal study only.
β¦ Synopsis
It is proved that the number of permuations on {I, 2, ... , n} with exactly one increasing subsequence of length 3 is ~(ntn3) [0,0,1,6,27,110,429, ... (Sloane A3517)].
Given a permutaion a E Sn, an abc subsequence is a set of three elements, a(i), aU), a(k), with a(i) < aU) < a(k) and i < j < k. It is known [2][3][4] that the number of permutations on {I, 2, ... , n} with no abc subsequences is given by the Catalan number 1/(n + 1)(~n). A natural question is: is there a nice expression for the generating function L~~~0 B(n, r)qr, where B(n, r) is the number of permutations on {I, 2, ... , n} with exactly r abc's, for 1 ~r ~m? Another question is, for a fixed r, what can one say about the sequence in n, B(n, r)? Doron Zeilberger conjectures that for any given r, the coefficients B(n, r) of the generating function are P-recursive in n, i.e. they satisfy a linear recurrence with polynomial coefficients. This is supported by the fact that
π SIMILAR VOLUMES
The purpose of this note is to give a new upper bound of the shortest string containing all r-permutations. Thus we disprove the conjecture considered in Cl]. The terminology used in this note fullows [I]. Koutas and Nu [I] proposed the foIlowing problem of constructing a shortest string of (1, 2,