The crystal structure of “bis(trimethyltin)-1,3,4-thiadiazole-2,5-dithiolate” – different bonding of the two trimethyltin groups

✍ Scribed by Engel, Günther; Mattern, Günter

• Book ID: 120162631
• Publisher: Oldenbourg Wissenschaftsverlag
• Year: 2008
• Tongue: English
• Weight: 144 KB
• Volume: 223
• Category: Article
• ISSN: 2194-4946
• DOI: 10.1524/zkri.2008.0050

✦ Synopsis

Abstract

[(CH~3~)~3~Sn]~2~S~2~(C~2~N~2~S) is monoclinic, space group __P__2~1~
/c, a = 10.492(5), b = 12.257(6), c = 12.691(6) Å, β
= 95.86(1)°. The zigzag chain structure of the coordination polymer can be derived by the structure correlation method. The starting point is a monomolecular symmetric bis(trimethyltin)-1,3,4-thiadiazole-2,5-dithiolate (Me~3~SnS)~2~ (C~2~N~2~S): The first of the Me~3~SnS moieties, bound to the atom C^5^ of the heterocyclus, remains tetrahedral, whereas the other, bound to C^2^, is transformed through the N^3^ atom of the neighbouring ring to a trigonal bipyramid S···(Me~3~Sn)···N. The three C atoms and the Sn atom of this Me~3~Sn group are nearly coplanar and form the equatorial plane. With the N^3^ atom of the starting molecule, an equivalent linking to the other neighbour takes place. The resultant plane ribbons run parallel to the crystallographic b-axis. The analysis of the bond distances and angles reveals that the regular trigonal bipyramid almost exactly represents the transition state along a chemical reaction pathway for a nucleophilic S~N~2 displacement at tetrahedrally coordinated tin.