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Reaction of (C 5 Me 5 ) 2 Yb(ER)(NH 3 ) with Me 3 Al. Formation of (C 5 Me 5 ) 2 Yb(AlMe 4 ) and [(C 5 Me 5 ) 2 Yb(ER)(AlMe 3 ) 2 ] 2

✍ Scribed by Berg, David J.; Andersen, Richard A.

No coin nor oath required. For personal study only.

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