## Abstract In this paper we exhibit a class of trees with the property that if __T__~__k__~ is a tree on __k__ vertices that belongs to this class, then necessary and sufficient conditions for __K__~__n__~ to have a __T__~__k__~‐factorization are simply __n__ = 0 (mod k) and __n__ = 1 (mod 2(__k__
Rainbow and orthogonal paths in factorizations of Kn
✍ Scribed by András Gyárfás; Mehdi Mhalla
- Publisher
- John Wiley and Sons
- Year
- 2010
- Tongue
- English
- Weight
- 164 KB
- Volume
- 18
- Category
- Article
- ISSN
- 1063-8539
No coin nor oath required. For personal study only.
✦ Synopsis
For n even, a factorization of a complete graph K n is a partition of the edges into n-1 perfect matchings, called the factors of the factorization. With respect to a factorization, a path is called rainbow if its edges are from distinct factors. A rainbow Hamiltonian path takes exactly one edge from each factor and is called orthogonal to the factorization. It is known that not all factorizations have orthogonal paths. Assisted by a simple edge-switching algorithm, here we show that for n ≥ 8, the rotational factorization of K n , GK n has orthogonal paths. We prove that this algorithm finds a rainbow path with at least (2n+1)/3 vertices in any factorization of K n (in fact, in any proper coloring of K n ). We also give some problems and conjectures about the properties of the algorithm.
📜 SIMILAR VOLUMES
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## Abstract Let ${\cal F}$ be a 1‐factorization of the complete uniform hypergraph ${\cal G}={K\_{rn}^{(r)}}$ with $r \geq 2$ and $n\geq 3$. We show that there exists a 1‐factor of ${\cal G}$ whose edges belong to __n__ different 1‐factors in ${\cal F}$. Such a 1‐factor is called a “rainbow” 1‐fact