We consider the minimum number of zeroes in a 2m × 2n (0, 1)-matrix M that contains no m × n submatrix of ones. We show that this number, denoted by f (m, n), is at least 2n + m + 1 for m ≤ n. We determine exactly when this bound is sharp and determine the extremal matrices in these cases. For any m
On the maximum density of 0–1 matrices with no forbidden rectangles
✍ Scribed by David Peleg
- Publisher
- Elsevier Science
- Year
- 1995
- Tongue
- English
- Weight
- 215 KB
- Volume
- 140
- Category
- Article
- ISSN
- 0012-365X
No coin nor oath required. For personal study only.
✦ Synopsis
This note provides bounds for the maximal number of ones allowed in an N x N 0-1 matrix, N = 2 n, in which there are no 'forbidden rectangles' of a special type.
1. Introduction
The density of a 0-1 matrix is defined as the number of l's that occur in it. A typical problem in extremal combinatorics (cf. [1,2]) involves the maximum density of a 0-1 matrix with a certain forbidden configuration. This note handles a specific question of this type, arising from [3].
Consider an N x N 0-1 matrix M. The rows and columns of M are numbered 0 ..... N-I.
A rectanffle in the matrix M is a quadruple (011,0~2, fll, f12) , for 0 ~< ctt, 0t2, fl,, f12 ~< N-1. The rectangle (~q, ~2, fl,, f12) is said to be full if
It is well known that the maximum density in an N x N 0-1 matrix with no full rectangle is O (N a/2) (cf. [2] ). The question we are actually interested in is slightly more complex. It is assumed that the size of the matrix is a power of 2, N = 2 n. We think of the row and column numbers of the matrix as given in binary representation, i.e., each row or column number is represented as a string of n bits ~=~n-t ...~lCtO • In the problem we consider, not all rectangles are forbidden. Rather, a rectangle Supported in part by an AIIon Fellowship, by a Bantrell Fellowship and by a Walter and Elise Haas Career Development Award.
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