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On the extender algebra being complete

✍ Scribed by Richard Ketchersid; Stuart Zoble

Publisher
John Wiley and Sons
Year
2006
Tongue
English
Weight
116 KB
Volume
52
Category
Article
ISSN
0044-3050

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✦ Synopsis

Abstract

We show that a Woodin cardinal is necessary for the extender algebra to be complete. Our proof is relatively simple and does not use fine structure. (Β© 2006 WILEY‐VCH Verlag GmbH & Co. KGaA, Weinheim)

πŸ“œ SIMILAR VOLUMES

Finite Complete Intersection Algebras an
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Let A be a ring, and let B be a finite A-algebra. If B is of the form w x Ε½ . A X , . . . , X r f , . . . , f then we say that B is a complete intersection over A.

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Two actions of the Hecke algebra of type A on the corresponding polynomial ring are studied. Both are deformations of the natural action of the symmetric group on polynomials, and keep symmetric functions invariant. We give an explicit description of these actions, and deduce a combinatorial formula