This paper investigates how many queries to k-membership comparable sets are needed in order to decide all (k + 1)-membership comparable sets. For k ยฟ 2 this query complexity is at least linear and at most cubic. As a corollary, we obtain that more languages are O(log n)-membership comparable than t
On Membership Comparable Sets
โ Scribed by D. Sivakumar
- Publisher
- Elsevier Science
- Year
- 1999
- Tongue
- English
- Weight
- 130 KB
- Volume
- 59
- Category
- Article
- ISSN
- 0022-0000
No coin nor oath required. For personal study only.
โฆ Synopsis
A set A is k(n) membership comparable if there is a polynomial-time computable function that, given k(n) instances of A of length at most n, excludes one of the 2 k(n) possibilities for the memberships of the given strings in A. We show that if SAT is O(log n) membership comparable, then the NP-hard promise problem UniqueSAT can be solved in polynomial time. Our result settles an open question, suggested by Buhrman, Fortnow, and Torenvliet, and extends the work of Ogihara, Beigel, Kummer, Stephan, and Agrawal and Arvind. These authors showed that if SAT is c log n membership comparable for c<1, then NP=P, and that if SAT is O(log n) membership comparable, then UniqueSAT # DTIME[2 log 2 n ]. Our proof also shows that if SAT is o(n) membership comparable, then UniqueSAT can be solved in deterministic time 2 o(n) . Our main technical tool is an algorithm of Madhu Sudan (building on the work of Ar, Lipton, Rubinfeld, and Sudan) to reconstruct polynomials from noisy data through the use of bivariate polynomial factorization.
๐ SIMILAR VOLUMES