It was proved by Chartrand f hat if G is a graph of order p for which the minimum degree is at least [&I, then the edge-connectivity of G equals the minimum degree of G. It is shown here that one may allow vertices of degree less than $p and still obtain the same conclusion, provided the degrees are
On graphs with equal edge connectivity and minimum degree
✍ Scribed by Béla Bollobás
- Publisher
- Elsevier Science
- Year
- 1979
- Tongue
- English
- Weight
- 255 KB
- Volume
- 28
- Category
- Article
- ISSN
- 0012-365X
No coin nor oath required. For personal study only.
✦ Synopsis
If a grrrph G hao edge connectivity A then the vertex fiat ha a partition V(a) = U U W ash that 61 esntainti exactly A edgea from U to W, Wen~se if Qo ia a maximal graph of order n and edge connectivity A than C$, is sbtctined from the dkjsint union of two complete oubgragh8, B,[U] and &T,[ Wg, by adding A edgea from Ur to W. (Here and in the sequel we use the notation of [I],) we may aaume without IOBB of generality that 1 Ul = k 1 WI = m, The rret U eantaina a vertex that i$ adjacent to at ma@t LA/k] vartic in W; wo S(B,,) Since $(a) B A, this imgliea that one of the fallowing four C~IXS holds:
(1) k = 1, (ii) k = A and every vertex in U 1~ adjacent to exactly one vertex in W, (iii) k = A =t= 1 and B(C3,) = A, (iv) k a A + ii afid 43(<Ta) = k -f 3 Ai h the! Atist three QE~MBI A(@,) y g(g,,) an# &~ce
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