N,N′-Bis(4-iodophenyl)diazene N-oxide
✍ Scribed by Krivokapić, Alexander ;Wilson, Craig J. ;Watkin, David J. ;Anderson, Harry L.
- Publisher
- International Union of Crystallography
- Year
- 2003
- Tongue
- English
- Weight
- 223 KB
- Volume
- 59
- Category
- Article
- ISSN
- 1600-5368
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✦ Synopsis
The title compound, C 12 H 8 I 2 N 2 O, was obtained as an unexpected product while attempting to protect N,N-dibutyl-4-iodoaniline as the N-oxide. It crystallizes as a layer structure.
Oxidation of (II) by hydrogen peroxide gives the N-oxide (III). This eliminates butene via a Cope reaction (Adams & Kovacic, 1974) before being oxidized again [to give (IV)] and undergoing a second elimination [to give (V)]. Di(hydroxyl)amine (V) then eliminates water to give nitrosamine (VI). From this point, it is likely that the mechanism is similar to that of the reaction between nitrosobenzene and phenylhydroxylamine (Becker & Sternson, 1980) [a radical mechanism is also seen in the presence of base (Russell et al.,
📜 SIMILAR VOLUMES
The title complex, C 21 H 21 N, crystallizes in space group P1, with Z = 6. The N atom is sp 2 -hybridized. The geometry of each of the three independent molecules is unremarkable. The interaction of the three molecules is discussed.
Single-crystal X-ray study T = 293 K Mean '(C±C) = 0.006 A Ê R factor = 0.042 wR factor = 0.110 Data-to-parameter ratio = 15.3 For details of how these key indicators were automatically derived from the article, see http://journals.iucr.org/e.
The title compound, C 36 H 58 N 2 O 3 , also known as a liquid crystalline material, has a phase sequence of crystal-smectic C-isotropic liquid. The two benzene rings are nearly coplanar with the central NNO group, and each paraffin chain has an all-trans conformation. The molecules form a tilted la