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Kernels in graphs with a clique-cutset

✍ Scribed by Henry Jacob


Publisher
Elsevier Science
Year
1996
Tongue
English
Weight
138 KB
Volume
156
Category
Article
ISSN
0012-365X

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✦ Synopsis


We consider graphs that have a clique-cutset, and we show that this property preserves the existence of a kernel in a certain sense.

We consider finite directed graphs that do not have multiple arcs or loops, but there may be symmetric arcs between some pairs of vertices. Let G = (V, A) be a directed graph, where V is the vertex-set and A is the arc-set. A kernel of G is a subset K of vertices such that (a) every vertex of G-K has a successor in K (the kernel is absorbant) and (b) there is no arc between any two vertices of the kernel (the kernel is stable). Not every directed graph admits a kernel; in fact it was shown by Chvhtal [2] that deciding if a graph possesses a kernel is an NP-complete problem; this result was strengthened by Fraenkel . On the other hand, many conditions are known that imply the existence of a kernel, see e.g. . Such conditions are usually hereditary, and so they also imply the existence of a kernel for every induced subgraph. A directed graph such that every induced subgraph has a kernel is called kernel-perfect. By similarity with other topics in graph theory, it is interesting to know what kind of graph constructions preserve kernel-perfectness. Here we consider the clique cutset. A clique-cutset is a subset C of vertices such that C is a clique and G -C is disconnected. For each connected component A of G-G we call the subgraph induced by A uC a piece of G with respect to C. The subgraph of G induced by a subset S will be denoted by G [S]. The main result of this paper is the following:

Theorem 1. Let G be a directed graph which admits a clique-cutset C. Then G is kernel-perfect if and only if every piece of G with respect to C is kernel-perfect.

This theorem should be viewed in parallel with some similar classical results in graph theory, in particular: if a graph admits a clique-cutset C, then it is


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