Let G be a 4connected infinite planar graph such that the deletion of any finite set of vertices of G results in at most one infinite component. We prove a conjecture of Nash-Williams that G has a 1 -way infinite spanning path. 0 1996 John Wiley & Sons, Inc. [7] has shown that every 4-connected fini
Infinite paths in planar graphs III, 1-way infinite paths
β Scribed by Xingxing Yu
- Publisher
- John Wiley and Sons
- Year
- 2006
- Tongue
- English
- Weight
- 336 KB
- Volume
- 51
- Category
- Article
- ISSN
- 0364-9024
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β¦ Synopsis
An infinite graph is 2-indivisible if the deletion of any finite set of vertices from the graph results in exactly one infinite component. Let G be a 4-connected, 2-indivisible, infinite, plane graph. It is known that G contains a spanning 1-way infinite path. In this paper, we prove a stronger result by showing that, for any vertex x and any edge e on a facial cycle of G, there is a spanning 1-way infinite path in G from x and through e. Results will be used in two forthcoming papers to establish a conjecture of Nash-Williams.
π SIMILAR VOLUMES
Nash-Williams conjectured that a 4-connected infinite planar graph contains a spanning 2-way infinite path if, and only if, the deletion of any finite set of vertices results in at most two infinite components. In this article, we prove this conjecture for graphs with no dividing cycles and for grap
## Abstract Let __G__ be an infinite 4βconnected planar graph such that the deletion of any finite set of vertices from __G__ results in exactly one infinite component. Dean __et al__. proved that either __G__ admits a radial net or a special subgraph of __G__ admits a ladder net, and they used the
## Abstract A graph is __kβindivisible__, where __k__ is a positive integer, if the deletion of any finite set of vertices results in at most __k__ β 1 infinite components. In 1971, NashβWilliams conjectured that a 4βconnected infinite planar graph contains a spanning 2βway infinite path if and onl