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(E)-N-Benzoyl-N′-(3-hydr­oxy-4-methoxy­benzyl­idene)hydrazine

✍ Scribed by Shi, Jun

Publisher
International Union of Crystallography
Year
2005
Tongue
English
Weight
158 KB
Volume
61
Category
Article
ISSN
1600-5368

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📜 SIMILAR VOLUMES

N,N′-Bis(3-hydr­oxy-4-methoxy­benzyl­ide
N,N′-Bis(3-hydr­oxy-4-methoxy­benzyl­idene)hydrazine
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The title compound, C 16 H 16 N 2 O 4 , was synthesized by the reaction of 3-hydroxy-4-methoxybenzaldehyde with hydrazine hydrate. The molecule possesses a crystallographically imposed centre of symmetry. An intramolecular O-HÁ Á ÁO hydrogen bond promotes planarity of the molecular backbone. In the

N′-(4-Hydr­oxy-3-methoxy­benzyl­idene)is
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The asymmetric unit of the title compound, C~14~H~13~N~3~O~3~·H~2~O, contains one molecule of __N__′-(4-hydroxy-3-methoxybenzylidene)isonicotinohydrazide and one solvent water molecule. The crystal packing is stabilized by O—H...N and O—H...O hydrogen bonds.

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N′-(4-Hydr­oxy-3-methoxy­benzyl­idene)-2-methoxy­benzohydrazide ethanol hemisolvate
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In the title compound, C 16 H 16 N 2 O 4 Á0.5CH 3 CH 2 OH, the Schiff base is approximately planar. An intramolecular N-HÁ Á ÁO hydrogen bond stabilizes the molecular structure. The molecules are linked by O-HÁ Á ÁO hydrogen bonds to form a chain along the b axis.

(E)-N′-(4-But­oxy-3-methoxy­benzyl­idene
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The vanillin residue makes dihedral angles of 4.84 (18) and 11.96 (7) with the planes of the butyl group and the terminal benzene ring, respectively. Intermolecular N-HÁ Á ÁO and C-HÁ Á ÁO hydrogen bonds help to consolidate the crystal packing.