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Dedekind's Theorem:$\sqrt{2} \times \sqrt{3} = \sqrt{6}$

✍ Scribed by David Fowler

Book ID: 124169862
Publisher: Mathematical Association of America
Year: 1992
Tongue: English
Weight: 929 KB
Volume: 99
Category: Article
ISSN: 0002-9890
DOI: 10.2307/2324238

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