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Cut-elimination and Redundancy-elimination by Resolution

✍ Scribed by Matthias Baaz; Alexander Leitsch

Publisher
Elsevier Science
Year
2000
Tongue
English
Weight
379 KB
Volume
29
Category
Article
ISSN
0747-7171

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A(s) -+ A(&zA(z)), ## HE^) Vz(A(z) ++ B ( z ) ) 4 KIA(%) = ~y B ( y ) . It was pointed out in [3] that HE^) makes this calculus non-conservative over the equality-free part. Namely, some formulas that do not contain equality can be proved only with the help of ( H e 2 ) (cf. also [Z], pp. 83, 84.