Abstract
Time‐dependent uv absorption and CD spectrum changes in salt‐induced conformational B → Z and Z → B transitions of poly(dGdC) · poly(dGdC) were measured. This polynucleotide does not convert directly from a right‐handed double‐helical B form to a left‐handed double‐helical Z form, but goes through an intermediate, B* form, with the B → B* transition proceeding nearly instantaneously, and then transforms gradually to the Z form. Uv absorption spectra of these B and B* forms are nearly identical, but their CD spectra are quite different. The CD spectrum of the B* form is identical with that obtained for DNA in high salt solutions and is similar to a spectrum which for some time was thought to be a C form. These B and B* forms have the same number of base pairs per turn [Sprecher, C.A., Baase, W.A. & Johnson, Jr., W.C. (1979) Biopolymers 18, 1009–1019]. Kinetic measurements showed that uv absorption and CD intensities at fixed wavelengths do not change in a simple exponential curve. However, both the uv absorption spectrum change in the B → Z transition and the CD spectrum change in the B* → Z transition, respectively, have isosbestic points. In the B → Z transition, no hyperchromicity can be observed. These results suggest that this B* form unfolding or premelting process is a rate‐determining step in the B* → Z transition and makes it easy for the unfolded or premelted polynucleotide to almost immediately fold into the Z form. The double helix does not dissociate into single strands and transforms from the B* form to the Z form point‐by‐point along the chain in a soliton‐like manner of with a small amount of open states in which the bases are unpaired. Also, in the Z → B transition, the polynucleotide does not convert directly from the Z to the B form, but goes through a B*‐like form. In this transition, the uv‐absorption spectra also have an isosbestic point. The reaction velocity in the Z → B transition is much faster than that in the B → Z transition. Possibly, the positive CD band between 265 and 310 nm in the B form comes from a n‐π* transition due to an interaction of the bases with sugarphosphate groups.