The result stated in the title is proved in this note. Actually we show that S x N is not a circle order, where S = {( 1, I), (1,2), (1,3), (2, I), (2, 3)}. Furthermore this non-circle order is critical in the sense that (S -{x}) x N is a circle order for any x in S.
β¦ LIBER β¦
A short proof thatN3is not a circle containment order
β Scribed by Glenn H. Hurlbert
- Publisher
- Springer Netherlands
- Year
- 1988
- Tongue
- English
- Weight
- 100 KB
- Volume
- 5
- Category
- Article
- ISSN
- 0167-8094
No coin nor oath required. For personal study only.
β¦ Synopsis
A partially ordered set P is called a circle containment order provided one can assign to each x e P a circle C x so that x <~ y Β’=~ Cx c_ Cy. We show that the infinite three-dimensional poset N 3 is not a circle containment order and note that it is still unknown whether or not [n] 3 is such an order for arbitrarily large n.
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