The bottleneck graph partition problem consists of partitioning the vertices of an undirected edge-weighted graph into two equally sized sets such that the maximum edge weight in the cut separating the two sets becomes minimum. In this short note, we present an optimum algorithm for this problem wit
A note on a cycle partition problem
โ Scribed by Fengli Yang; Elkin Vumar
- Publisher
- Elsevier Science
- Year
- 2011
- Tongue
- English
- Weight
- 209 KB
- Volume
- 24
- Category
- Article
- ISSN
- 0893-9659
No coin nor oath required. For personal study only.
โฆ Synopsis
Let G be any graph, and let c(G) denote the circumference of G. If, for every pair c 1 , c 2 of positive integers satisfying c 1 + c 2 = c(G), the vertex set of G admits a partition into two sets V 1 and V 2 such that V i induces a graph of circumference at most c i , i = 1, 2, then G is said to be c-partitionable. In [M.H. Nielsen, On a cycle partition problem, Discrete Math. 308 (2008) 6339-6347], it is conjectured that every graph is c-partitionable. In this paper, we verify this conjecture for a graph with a longest cycle that is a dominating cycle. Moreover, we prove that G is c-partitionable if c(G) โฅ |V (G)| -3.
๐ SIMILAR VOLUMES
We give a simple proof that the number of graphical partitions of an even positive integer \(n\) is at least \(p(n)-p(n-1) . \quad 1995\) Academic Press. Inc.